Question

Consider the compounds, $BC{l}_3$ and $CC{l}_4$. How will they behave with water? Justify.

Answer 1

Being a Lewis acid, $BC{l}_3$ readily undergoes hydrolysis. Boric acid is formed as a result.
$BC{l}_3+3H_{2}O⟶3HCl+B(OH{)}_3$
$CC{l}_4$ completely resists hydrolysis. Carbon does not have any vacant orbital. Hence, it cannot accept electrons from water to form an intermediate. When $CC{l}_4$ and water are mixed, they form separate layers.
$CC{l}_4+H_{2}O⟶Noreaction$