Consider the conducting square loop shown in figure. If the switch is closed and after some time it is opened again, the closed loop will show:
A
a clockwise current-pulse
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B
an anticlockwise current-pulse
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C
an anticlockwise current pulse and then a clockwise pulse
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D
a clockwise current pulse and then an anticlockwise current pulse
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Solution
The correct option is A a clockwise current-pulse When the switch is closed the current in it is clockwise so when the switch is open current start to reach to zero very fast so flux decreases.
According to Lenz law the induced current pulse should oppose the change i.e., should oppose the decrease in current so induced current pulse will be clockwise to oppose the decrease.