Consider the coordination compound- Na 2- Pt CN 4- The Lewis acid isA- - Pt CN 4-2-B- Na -C- Pt 2-D- PtE- CN -

The correct option is C Pt2+ Lewis acid = gt; an electron acceptor Lewis base = gt; an electron donor A nbsp;coordination nbsp;co ...

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Potassium Dichromate

Consider the ...

Question

Consider the coordination compound, Na₂[Pt(CN)₄]. The Lewis acid is

[Pt(CN)₄]^2-

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Na⁺

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Pt²⁺

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CN^-

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N a_{2} [P t (C N)_{4}]

Predict the number of unpaired electrons in the square planar [Pt(CN)₄]²⁻ ion.

[N i (C N)_{4}]^{2 -}

[P t (C N)_{4}]^{2 -}

H_{2} O

N H_{3}

H^{+}

B F_{3}

A I H_{3}

R O H

C H_{3} N H_{2}

C N^{-}

^{+} C H_{3}

[C o (N H_{3})_{6}] C l_{3}

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