Consider the cross AaBbCcDdEe×aaBbccddee. What proportion of the progeny will genotypically resemble the first parent?
A
1/64
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B
2/64
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C
4/16
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D
4/46
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Solution
The correct option is A1/64
In such genetic cross, each gene is crossed separately and then probability of desired progeny is obtained by multiplying the probability of each gene as shown below:
Aa x aa Bb x Bb Cc x cc Dd x dd Ee x ee
↓ ↓ ↓ ↓ ↓
Aa Aa aa aa BB Bb bB bb Cc Cc cc cc Dd Dd dd dd Ee Ee ee ee
Probability of :
Aa is 2/4, Bb is 1/4, Cc is 2/4, Dd is 2/4, Ee is 2/4
So, combined probability is 2/4x1/4x2/4x2/4x2/4=1/64