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Byju's Answer
Standard XII
Mathematics
Parametric Differentiation
Consider the ...
Question
Consider the curve
x
=
a
(
cos
θ
+
θ
sin
θ
)
and
y
=
a
(
sin
θ
−
θ
cos
θ
)
.
What is
d
y
d
x
equal to.
A
tan
θ
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B
cot
θ
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C
sin
2
θ
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D
cos
2
θ
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Solution
The correct option is
A
tan
θ
The given equation is:
x
=
a
(
cos
θ
+
θ
sin
θ
)
y
=
a
(
sin
θ
−
θ
cos
θ
)
Differentiating x and y w.r.t. to
θ
once we get,
⇒
d
y
d
θ
=
a
(
cos
θ
−
cos
θ
+
θ
sin
θ
)
⇒
d
y
d
θ
=
a
θ
sin
θ
⇒
d
x
d
θ
=
a
(
sin
θ
−
sin
θ
+
θ
cos
θ
)
⇒
d
x
d
θ
=
a
θ
cos
θ
Dividing the two equations we get,
⇒
d
y
d
x
=
a
θ
sin
θ
a
θ
cos
θ
⇒
d
y
d
x
=
tan
θ
.....Answer
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Similar questions
Q.
Find
d
y
d
x
if
x
=
a
(
cos
θ
+
θ
sin
θ
)
. and
y
=
a
(
sin
θ
−
θ
cos
θ
)
.
Q.
The normal to the curve
x
=
a
(
c
o
s
θ
+
θ
s
i
n
θ
)
,
y
=
a
(
s
i
n
θ
−
θ
c
o
s
θ
)
at any point
′
θ
′
is such that
Q.
If
x
=
a
(
cos
θ
+
θ
sin
θ
)
,
y
=
a
(
sin
θ
−
θ
cos
θ
)
,
then
d
2
x
d
θ
2
=
a
(
cos
θ
−
θ
sin
θ
)
,
d
2
y
d
θ
2
=
a
(
sin
θ
+
θ
cos
θ
)
Q.
If x = a (cos θ + θ sin θ), y = a (sin θ – θ cos θ), prove that
d
2
x
d
θ
2
=
a
cos
θ
-
θ
sin
θ
,
d
2
y
d
θ
2
=
a
sin
θ
+
θ
cos
θ
and
d
2
y
d
x
2
=
sec
3
θ
a
θ
.
Q.
The normal to the curve given by
x
=
a
(
cos
θ
+
θ
sin
θ
)
,
y
=
a
(
sin
θ
−
θ
cos
θ
)
at any point
θ
is such that it
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