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Question

Consider the curve x=a(cosθ+θsinθ) and y=a(sinθθcosθ).
What is dydx equal to.

A
tanθ
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B
cotθ
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C
sin2θ
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D
cos2θ
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Solution

The correct option is A tanθ
The given equation is:

x=a(cosθ+θsinθ)

y=a(sinθθcosθ)

Differentiating x and y w.r.t. to θ once we get,

dydθ=a(cosθcosθ+θsinθ)

dydθ=aθsinθ

dxdθ=a(sinθsinθ+θcosθ)

dxdθ=aθcosθ

Dividing the two equations we get,

dydx=aθsinθaθcosθ

dydx=tanθ .....Answer

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