Consider the following balanced reaction with minimum integral coefficients. $x F e S_{2} + y N a_{2} O_{2} + z H_{2} S O_{4} \to p N a_{2} F e O_{4} + q N a_{2} S O_{4} + r H_{2} O$
Find the correct option(s):

x = 2, p = 2

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y = 4, p =1

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y = 9, r = 6

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z = 6, q = 8

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Solution

The correct option is D z = 6, q = 8
The balanced reaction is:
$F e S_{2} + 9 N a_{2} O_{2} + 6 H_{2} S O_{4} \to N a_{2} F e O_{4} + 8 N a_{2} S O_{4} + 6 H_{2} O$
From the above reaction, we have:
x = 1, y = 9, z = 6 and
p = 1, q = 8, r = 6.

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