Consider the following Carbocations : I) C6H5←CH2 II) C6H5←CH2CH2 III) C6H5←CH←CH3 IV) C6H5←C(CH3)2
A
I>II>III>IV
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B
II>I>III>IV
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C
IV>III>II>I
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D
IV>III>I>II
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Solution
The correct option is D IV>III>I>II The stability of carbocation is increased in presence of phenyl ring (due to conjugation) and methyl groups (due to their electron-pushing tendency). More the methyl groups, more is the stability. Hence IV will be most stable, followed by III and then by I. II will be least stable as the carbocation does not have resonance stabilization.