Consider the following cell reaction- 2Fes - O2 g - 4H- aq - 2Fe2- aq - 2H2Ol- Eo - 1-67 VAt -Fe2- - 10-3 M- PO2 - 0-1 atm and pH - 3- the cell potential at 25oC is-

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Nernst Equation

Consider the ...

Question

Consider the following cell reaction:
$2 F e (s) + O_{2} (g) + 4 H^{+} (a q) \to 2 F e^{2 +} (a q) + 2 H_{2} O (l), E^{o} = 1.67 V$
At $[F e^{2 +}] = 10^{- 3} M, P (O_{2}) = 0.1$ atm and $p H = 3$ , the cell potential at $25^{o}$ C is:

1.47 V

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1.77 V

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1.87 V

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1.57 V

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2 F e (s) + O_{2} (g) + 4 H^{+} (a q) \to 2 F e^{2 +} (a q) + 2 H_{2} O (l)

E^{-} = 1.67 V

[F e^{2 +}] = 10^{- 3} M, p (O_{2}) = 0.1

p H

3

25^{0}

2 F e (s) + O_{2} (g) + 4 H^{+} (a q) \to 2 F e^{2 +} (a q) + 2 H_{2} O (l); E^{\circ} = 1.67 V

[F e^{2 +}] = 10^{- 3} M, P_{(O_{2})} = 0.1 a t m

25^{\circ} C

\frac{2.303 R T}{F} = 0.0591

2 F e (s) + O_{2} (g) + 4 H^{+} (a q) \to 2 F e^{2 +} (a q) + 2 H_{2} O (l); E^{\circ} = 1.67 V

[F e^{2 +}] = 10^{- 3} M, P_{(O_{2})} = 0.1 a t m

25^{\circ} C

\frac{2.303 R T}{F} = 0.0591

E^{o}

[E_{(F e^{2 +} (a q) / F e)}^{o} = 0.44 V

E_{(O_{2} (g) / H_{2} O / O H^{-})}^{o} = + 0.4 V]

2 F e (s) + O_{2} (g) + 2 H_{2} O (l) ⇋ 2 F e^{2 +} (a q) + 4 O H^{-} (a q)

2 A g C l (s) + H_{2} (g) \to 2 A g (s) + 2 H^{+} (a q) + 2 C l^{-} (a q); E^{o} = 0.19 V

[C l^{-}] = 10^{- 3} M

P_{H_{2}} = 0.01 atm

V

25^{o} C

p H

(Take \frac{2.303 R \times 298}{F} = 0.06)

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