Consider the following chages M(s)→M(g)M(s)→M2+(g)+2e− M(g)→M+(g)+e−M+(g)→M2+(g)+e− M(g)→M2+(g)+2e− The second ionization energy of M could be calculated from the energy values associated with_________.
A
1+3+4
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B
2-1+3
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C
1+5
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D
5-3
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Solution
The correct option is D 5-3 The second ionization energy of M could be calculated from (5)-(3). 1. M(s)→M(g) 2. M(s)→M2+(g)+2e− 3. M(g)→M+g 4. M+(g)→M2+(g)+2e− 5. M(g)→M2+(g)+2e− I.P.=IP1+IP2 (5) = (3) + (4) (5) = I.P - IP1 or (5) - (3)