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Question

Consider the following changes
M(s)M(g) ...(1)
M(g)M2+(g)+2e ....(2)
M(g)M+(g)+e ....(3)
M+(g)M2+(g)+e ...(4)
M(g)M2+(g)+2e ...(5)
The second ionisation energy of M could be determined from the energy values associated with:

A
1+2+4
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B
1+53
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C
2+34
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D
53
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Solution

The correct option is D 53
The amount of energy required to take out an electron from the monopositive cation is called second ionisation energy
M(g)M2+(g)+2e (v)
M(g)M+(g)+e (iii)
On subtracting equation (iii) from equation (v) we get,
MM2++e.

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