Question

Consider the following circuit:
For the circuit shown above, by how much the voltage across the inductor leads the voltage acrioss the capacitor?

• A. $45$
• B. $90$
• C. $135$
• D. $180$

Answer 1

The correct option is A $45$

REF.Image

$I=\frac{2\angle 0^{\circ }}{X_c}+\frac{2\angle 0}{R}$

$=\frac{2\angle 0^{\circ }}{-j}+\frac{2\angle 0}{1}$

$=2j+2$

$\therefore V_L=I{X}_L=(2j+2)\left(j2L\right)$

$=-4+4j$

$\theta =ta{n}^{-1}\frac{4}{-4}=ta{n}^{-1}-1=\frac{-\pi }{4}$