Consider the following complex ions: P,Q, and R. P=[FeF6]3−,Q=[V(H2O)6]2+ and R=[Fe(H2O)6]2+
The correct order of the complex ions, according to their spin only magnetic moment values (in BM) is:
A
Q<R<P
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B
R<Q<P
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C
R<P<Q
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D
Q<P<R
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Solution
The correct option is AQ<R<P μspin only=√n(n+2)
Magnetic moment arises due to the presence of unpaired electrons.
More the number of unpaired electrons, greater will be the magnetic moment. P has Fe in +3 oxidation state. Fe(+3):3d5 Q has V in +2 oxidation state. V(+2):3d3 R has Fe in +2 oxidation state. Fe(+2):3d6
Hence the number of unpaired electrons in P,Q and R are 5,3 and 4 respectively.