wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider the following complex ions:
P, Q, and R. P=[FeF6]3, Q=[V(H2O)6]2+ and R=[Fe(H2O)6]2+
The correct order of the complex ions, according to their spin only magnetic moment values (in BM) is:

A
Q<R<P
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
R<Q<P
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
R<P<Q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Q<P<R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Q<R<P
μspin only=n(n+2)
Magnetic moment arises due to the presence of unpaired electrons.
More the number of unpaired electrons, greater will be the magnetic moment.
P has Fe in +3 oxidation state.
Fe(+3):3d5
Q has V in +2 oxidation state.
V(+2):3d3
R has Fe in +2 oxidation state.
Fe(+2):3d6
Hence the number of unpaired electrons in P,Q and R are 5,3 and 4 respectively.

flag
Suggest Corrections
thumbs-up
11
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Octahedral Complexes
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon