Consider the following complexes.
(i) $[C r (E D T A)]^{-}$
(ii) $[R u (e n)_{3}]^{2 +}$
(iii) $[P t (g l y)_{2} C l_{2}]^{- 2}$
(iv) $C i s - [C r (C l)_{2} (o x)_{2}]^{3 -}$
(v) trans - $[P t (e n) (N H_{3})_{2} (p y)_{2}]^{4 +}$
Then find out the value of expression $| p + q |^{2}$
$p = total number of optically active complexes$
$q = total number of optically inactive complexes$

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Solution

$(i) [C r (E D T A)]^{-}$

It has 2 optically active isomers as it has no plane plane of symmetry.
(ii) $[R u (e n)_{3}]^{2 +}$

This complex do not have element of symmetry. Hence, optically active.
(iii) $P t (g l y)_{2} C l_{2}]^{2 -}$

Here both the two trans forms are optically inactive but cis form shows 4 optically active isomers.
(iv) $C i s - [C r (C l)_{2} (o x)_{2}]^{3 -}$
It shows 2 optically active isomers.
(v) trans - $[P t (e n) (N H_{3})_{2} (p y)_{2}]^{4 +}$

Optically inactive due to presence of plane of symmetry.
Since $p = 8 q = 2 | p + q |^{2} = | 10 + 3 |^{2} = 169$

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Consider the following complexes. (i) [Cr(EDTA)]− (ii) [Ru(en)3]2+ (iii) [Pt(gly)2Cl2]−2 (iv) Cis−[Cr(Cl)2(ox)2]3− (v) trans - [Pt(en)(NH3)2(py)2]4+ Then find out the value of expression |p+q|2 p=total number of optically active complexes q=total number of optically inactive complexes