Question

Consider the following compounds and distinguishing tests. List–I contains compounds for the test and List–II contains test which distinguish the given pair of compounds.


Which of the following option has correct combination considering List–I and List–II?

• A. (I) - (Q), (S)
• B. (I) - (Q)
• C. (I) - (P)
• D. (III) - (R)

Answer 1

The correct option is C (I) - (P)

(I) Both are secondary alcohols so can not be differentiated by Lucas test. $-\stackrel{OH}{\stackrel{|}{C}}-C{H}_3$ gives positive iodoform test.
Hence these can be differentiated by iodoform test.
$\therefore I\to P$

(II) First compound gives white ppt of $AgCl$ with aq. $AgN{O}_3$. Second compound gives positives Lucas test.
$\therefore II\to Q,S$

(III) Phenol being weakly acidic does not react with sodium bicarbonate while carboxylic acid releases $C{O}_2$ on reaction with $NaHC{O}_3$.
$\therefore III\to T$

(IV) These can be differentiated through isocyanide test. Only primary amines respond positively to this test.
$\therefore IV\to R$