Question

Consider the following electronic energy level diagram of H - atom, photons associated with shortest and longest wavelength would be emitted from the atom by the transitions of

• A. D and C respectively
• B. C and A respectively
• C. C and D respectively
• D. A and C respectively

Answer 1

The correct option is C C and D respectively

Difference in energy level
$\Delta E=Rc{z}^2(\frac{1}{n_1^2}-\frac{1}{n_2^2})=\frac{hc}{\lambda }$

from $n=4\to n=2$
$\Delta E$ = maximum energy
wavelength $\lambda$ will be shortest for C
If transition occurs from $n=4\to n=3$
then $\Delta E\to$ minimum
$\lambda$ will be longest for D.

$C\to$ Shortest
$D\to$ longest