Consider the following half cells Cu(s)→Cu2+(aq)+2e−;Eo=−0.325V Cu+(aq)+e−→Cu(s);Eo=0.50V
The Eo for the reaction 2Cu+(aq)→Cu2+(aq)+Cu(s) is
A
0.175 V
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B
0.35 V
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C
0.675 V
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D
0.3375 V
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Solution
The correct option is A 0.175 V (1) Cu(s)→Cu2+(aq)+2e−;E∘1=−0.325V
(2) Cu+(aq)+e−→Cu(s);E∘2=0.50V
The required reaction is: 2Cu+(aq)→Cu2+(aq)+Cu(s)
We need to combine the two above mentioned reactions so as to form the final reaction and the resultant standard EMF will be a summation of the Eoof the combining reactions.