Question

Consider the following interaction of atomic orbitals.


Out of the above combination
$X=$ Number of non-bonding combinations.
$Y=$ Number of combinations that produce only antibonding molecular orbital.
$Z=$ Number of combinations that produce only bonding molecular orbital.
$V=$ Number of combinations that produce bonding $\pi$ molecular orbital.
$W=$ Number of combinations that produce antibonding $\pi \ast$ molecular orbital.
The value of $X+Y+Z+V^2+W$ is:

• A. 9.0
• B. 9
• C. 9.00

Answer 1

Answer: (A), (B), (C)

(a), (b), (c) $\to$ Non-bonding combinations
$\left(e\right),\left(f\right)\to \text{combinations that only produce antibonding molecular orbital}$
$\left(d\right)\to \text{combination that only produce bonding molecular orbital}$
$\left(d\right)\to \text{combination that produces bonding}\pi \text{molecular orbital}$
$\left(e\right),\left(f\right)\to \text{combinations that produce}{\pi }^{\ast }\text{antibonding molecular orbital}$
$X=3$
$Y=2$
$Z=1$
$V=1$
$W=2$
$\therefore X+Y+Z+V^2+W=3+2+1+(1{)}^2+2=9$