Consider the following nuclear reaction- xa P - k - -10-Then k is -

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Nuclear Fission

Consider the ...

Question

Consider the following nuclear reaction.
$_{x}^{a} P \to k +_{- 1}^{0} β$ .

Then $k$ is :

_{x + 1}^{a} Q

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

_{x - 1}^{a} Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

_{x + 1}^{a + 1} Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

_{x}^{a + 1} Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $_{x + 1}^{a} Q$
Atomic number of $Q$ is $x - (- 1) = x + 1$
Mass number of $Q$ is $a - 0 = a$ .
So, $_{x + 1}^{a} Q$

Suggest Corrections

Similar questions

Consider the following nuclear disintegration.

_{Z}^{A} X \to_{Z - 2}^{A + k} X +_{2}^{4} H e

. Then the value of

k

will be :

Q. Tick (✓) the correct answer:
pq² + q(p − 1) − 1 = ?
(a) (pq + 1)(q − 1)
(b) p(q + 1)(q − 1)
(c) q(p − 1)(q + 1)
(d) (pq − 1) (q + 1)

If $c o s^{- 1} (\frac{p}{a}) + c o s^{- 1} (\frac{q}{b}) =$ then $\frac{p^{2}}{a^{2}} + k c o s α + \frac{q^{2}}{b} = s i n^{2} α$ , where k is equal to

Q. If

\int_{- a}^{a} \sqrt{\frac{a - x}{a + x}} d x = k π,

then k = ________________.

$p q^{2} + q (p - 1) - 1 = ? (a) (p q + 1) (q - 1) (b) p (q + 1) (p - 1) (c) q (p - 1) (q + 1) (d) (p q - 1) (q + 1)$

Join BYJU'S Learning Program

Consider the following nuclear reaction. axP→k+0−1β.Then k is :

The correct option is A ax+1QAtomic number of Q is x−(−1)=x+1Mass number of Q is a−0=a.So, ax+1Q

Consider the following nuclear reaction.
$_{x}^{a} P \to k +_{- 1}^{0} β$ .

Then $k$ is :

The correct option is A $_{x + 1}^{a} Q$
Atomic number of $Q$ is $x - (- 1) = x + 1$
Mass number of $Q$ is $a - 0 = a$ .
So, $_{x + 1}^{a} Q$