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Question

Consider the following reaction,

C6H5NO2 Sn/HCl−−−−−→X C6H5COCl−−−−−−−→Y+HCl

What is Y?

A
Acetanilide
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B
Benzinilide
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C
Azobenzene
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D
Hydrazobenzene
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Solution

The correct option is C Benzinilide
Nitrobenzene is reduced to aniline when passed through tin and hydrochloric acid .
C6H5NO2Sn/HCl−−−−C6H5NH2

Followed by C6H5COCl gives,

C6H5NH2C6H5COCl−−−−−−C6H5NHCOC6H5

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