Question

In the reaction $C_6{H}_5{NH}_2\stackrel{{NaNO}_2+HCl,{0-5}^{0}C}{\to }X\stackrel{H_{2}O,warm}{\to }Y$

Y is :

• A. $C_6{H}_{5}Cl$
• B. $C_6{H}_6$
• C. $C_6{H}_{5}OH$
• D. $C_6{H}_{5}CHO$

Answer 1

The correct option is C $C_6{H}_{5}OH$

Benzene is diazotized with sodium nitrite and HCl at low temperatures to obtain benzene diazonium chloride (compound X). it s then treated with warm water to form phenol (compound Y).

$\underset{benzene}{C_6{H}_5{NH}_2}\stackrel{{NaNO}_2+HCl,{0-5}^{0}C}{\to }\underset{X,benzenediazoniumchloride}{C_6{H}_5{N}_2^{+}C{l}^{-}}\stackrel{H_{2}O,warm}{\to }\underset{Y,phenol}{C_6{H}_{5}OH}$

Y is $C_6{H}_{5}OH$.