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Hydrides of Nitrogen

Consider the ...

Question

Consider the following reaction: $N H_{4} C l + N a O H ⇌ H_{2} O + N H_{3} + N a C l$ .
Which substance would be considered the strongest acid in this chemical reaction, considering both the forward and reverse reactions?

N H_{4} C l

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N a O H

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H_{2} O

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N H_{3}

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Solution

The correct option is A $N H_{4} C l$
$N H_{4} C l + N a O H ⇋ H_{2} O + N H_{3} + N a C l$
In this reaction, $N a O H$ is the strong base and its conjugate acid $N a^{+}$ is weak.
The other acidic species in this reaction is $N H_{4} C l$ .
Considering backward reaction, $N H_{3}$ is a weak base but its conjugate acid $N H_{3}$ is the weak base but its conjugate acid $N H_{4}^{+}$ is a strong acid.
Hence, $N H_{4} C l$ is the strongest acid in this chemical reaction.

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Similar questions

A

N H_{4} C l

D

C O_{2}

B

C

+ N a O H \to N a C l + N H_{3} + H_{2} O

N H_{3} + C O_{2} + H_{2} O \to (B)

+ N a C l \to (C) + N H_{4} C l

\to N a_{2} C O_{3} + H_{2} O + (D)

N a C l + H_{2} O + C O_{2} + N H_{3}

\to

N H_{4} C l + X

C O_{2} + N H_{3} + H_{2} O \to X

X + N a C l \to Y + N H_{4} C l

N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + N H_{3} + H_{2} O

N H_{3}

0.535 g

N H_{4} C l

N a O H

N H_{4} C l + N a O H \to N H_{3} + N a C l + H_{2} O

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