The reaction is a disproportionation reaction:
Oxidation reaction:
P4→4H2PO−2+4e− ( P oxidation changed from 0 to +1)
Reduction reaction:
P4+12e−→4PH3 ( P reduction changed from 0 to -3)
P4→PH3+3H2PO−2
balance the by adding OH− on the left-hand side
P4+3OH−→PH3+3H2PO−2
Adding water to balance the hydrogen,
P4+3OH−+3H2O→PH3+3H2PO−2
x=3,y=3,z=3
x+y+z=9