Consider the following reaction sequence-S8s-8O2g- 8SO2g2SO2g-O2g- 2SO3gHow many moles of SO3 are produced from 10 moles of S8-

According to the reaction, 1 mol of S_8 produces 8 mol of SO_2 therefore, 10 mol of S_8 produce (8× 10)=80 mol of SO_2 Similarly, 2 mol of SO_2 produce 2 mol of ...

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Standard XII

Chemistry

Mole Concept

Consider the ...

Question

Consider the following reaction sequence:
$S_{8} (s) + 8 O_{2} (g) \to 8 S O_{2} (g)$
$2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)$
How many moles of $S O_{3}$ are produced from 10 moles of $S_{8}$ ?

10 mol

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20 mol

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40 mol

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80 mol

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Solution

The correct option is D $80 mol$
According to the reaction,
1 mol of $S_{8}$ produces 8 mol of $S O_{2}$
therefore, 10 mol of $S_{8}$ produce $(8 \times 10) = 80 mol of S O_{2}$
Similarly, 2 mol of $S O_{2}$ produce 2 mol of $S O_{3}$ .
So, 80 mol $S O_{2}$ will produce 80 mol $S O_{3}$ .

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Similar questions

Q. Consider the following reaction sequence:

S_{8} (s) + 8 O_{2} (g) \to 8 S O_{2} (g)

2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)

How many moles of

S O_{3}

are produced from 10 moles of

S_{8}

Q. Sulphur trioxide is prepared by the following two reactions:

S_{8} (s) + 8 O_{2} (g) \to 8 S O_{2} (g)

2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)

How many grams of

S O_{3}

are produced from

1

mole of

S_{8}

Q. Sulphur trioxide is prepared by the following two reactions:

S_{8} (s) + 8 O_{2} (g) \to 8 S O_{2} (g)

2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)

How many grams of

S O_{3}

arc produced from 1 mole of

S_{8}

Q. Consider the following reaction sequence:

S_{8} (s) + 80_{2} (g) \to {8 S O}_{2} (g)

{2 S O}_{8} (g) + O_{2} (g) \to {2 S O}_{3} (g)

How many grams of

{S O}_{3}

are produced from

1

mole

{S O}_{8}

Q. Sulphur trioxide may be prepared by the following two reactions:

S_{8} + 8 O_{2} (g) \to 8 S O_{2} (g)

2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)

.
How many grams of

S O_{3}

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1

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Consider the following reaction sequence: S8(s)+8O2(g)→8SO2(g) 2SO2(g)+O2(g)→2SO3(g) How many moles of SO3 are produced from 10 moles of S8?

The correct option is D 80 molAccording to the reaction, 1 mol of S8 produces 8 mol of SO2 therefore, 10 mol of S8 produce (8×10)=80 mol of SO2 Similarly, 2 mol of SO2 produce 2 mol of SO3. So, 80 mol SO2 will produce 80 mol SO3.

Consider the following reaction sequence:
$S_{8} (s) + 8 O_{2} (g) \to 8 S O_{2} (g)$
$2 S O_{2} (g) + O_{2} (g) \to 2 S O_{3} (g)$
How many moles of $S O_{3}$ are produced from 10 moles of $S_{8}$ ?

The correct option is D $80 mol$
According to the reaction,
1 mol of $S_{8}$ produces 8 mol of $S O_{2}$
therefore, 10 mol of $S_{8}$ produce $(8 \times 10) = 80 mol of S O_{2}$
Similarly, 2 mol of $S O_{2}$ produce 2 mol of $S O_{3}$ .
So, 80 mol $S O_{2}$ will produce 80 mol $S O_{3}$ .