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Molality

Consider the ...

Question

Consider the following reaction taking place completely.
$2 N a + 2 H_{2} O ⟶ 2 N a O H + H_{2}$
How many milligrams of $N a O H$ will be formed by $0.01$ mole of $N a$ ? (Given that $N a = 23, H = 1, O = 16$ )

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Solution

$1$ mole of $N a$ will form $1$ mole of $N a O H$ , which corresponds to $40$ g $\times 1000$ mg/g $= 40000$ mg.
Hence, $0.01$ mol of $N a$ will form $0.01 \times 40000 = 400$ mg of $N a O H$ .

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