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Stoichiometric Calculations

Consider the ...

Question

Consider the following reaction taking place completely.
$2 N a + 2 H_{2} O ⟶ 2 N a O H + H_{2}$
If the number of moles of $H_{2}$ formed from $0.46$ g of $N a$ is $x$ , then $100 x$ is :

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Solution

$2$ moles of $N a$ forms $1$ mole of hydrogen.
$0.46$ g of Na corresponds to $\frac{0.46 g}{23 g / m o l} = 0.02$ moles of $N a$ . They will form $0.01$ mole of hydrogen.
Hence, $x = 0.01$ mol.
or, $100 x = 1$ .

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