wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Consider the following reactions in which all the reactants and products are in gaseous state.
2PQ P2+Q2;K1=2.5× 105
PQ+12R2 PQR, K2=5× 103

The value of K3 for the equilibrium
1/2 P2+1/2Q2+1/2 R2 PQR

A
2.5 x 10-3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.5 x 103
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.0 x 10-5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5 x 103
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1.0 x 10-5

Correct option is c).
For 2PQ P2+Q2,K1=[P2][Q2]/[PQ]2
For PQ+12R2 PQR, K2=[PQR]([PQ][R]12)
For the required equilibrium
1/2 P2+1/2Q2+1/2 R2 PQR
K=[PQR]/([P2]12[Q2]12[R2]12=K2KT=5×103/(2.5×105)12=5× 103/5× 102=105


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equilibrium Constants
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon