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Consider the following statements and arrange in the order of true/false as given in the codes.
Here L is the lone pair
S1: In AB2L2 type, the BAB bond angle will be always greater than normal tetrahedral.
S2: Maleic acid has higher Ka1 value than fumaric acid due to intramolecular hydrogen bonding.
S3: In ClO3, NH3 and XeO3, the hybridisation and the number of lone pair(s) on central atoms are same.

A
TTT
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B
FTF
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C
FTT
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D
FFT
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Solution

The correct option is C FTT
S1:OF2<109.5o and OBr2>109.5o
OF2 (appx. 102o): Fluorine being more electronegative attracts the bond pairs of electrons towards itself and thus there is more lp-lp repulsion decreasing the bond angle.
OBr2(appx.113o): The bond pairs are close to more electronegative oxygen atom and thus there is repulsion between bp-bp increasing the bond angle. The bulkier Br atoms also create steric repulsion which also increase the bond angle.
S2: Anion of maleic acid (cis-form) gets stabilised through intramolecular hydrogen bonding after giving one proton as given in following structure. In fumaric acid (trans-form) no such intramolecular H-bonding is possible.
S3: All have sp3 hybridisation and one lone pair of electrons.

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