Question

Consider the following statements and arrange in the order of true/false as given in the codes.
$S_1$ : Both ${\left[Co{\left(ox\right)}_3\right]}^{3-}$ and ${\left[Co{F}_6\right]}^{3-}$ are paramegnetic.
$S_2:CoC{l}_{3}3N{H}_3$ complex is non-conducing.
$S_3$ : The number of possible isomers for the complex $\left[Pt\left(N{O}_2\right)\left(py\right)\left(OH\right)\left(N{H}_3\right)\right]$ is six.
$S_4$ : The oxidation state of iron in brown ring complex $\left[Fe{\left(H_{2}O\right)}_{5}N{O}^{+}\right]S{O}_4$ is +II where NO is $N{O}^{+}$

• A. F T T F
• B. T T T T
• C. F T T F
• D. T T T F

Answer 1

Answer: (C)

F T T F

• $S_1:\left[Co{F}_6{]}^{3-}\text{is paramagnetic with 5 unpaired electrons but}\right[Co(ox{)}_3{]}^{3-}\text{is diamagnetic as all electrons}$ $\text{are paired.}$
• $S_2:\text{It exists as}\left[Co\right(N{H}_3{)}_{3}C{l}_3],\text{neutral molecule.}$
• $S_3:\text{It is a correct statement. It shows linkage and geometrical isomerism.}$
• $S_4:\left[Fe\right(+I\left)\right(H_{2}O{)}_{5}N{O}^{+}]S{O}_4^{2-}$

Option C is correct.