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Question

Consider the following statements and arrange in the order of true/false as given in the codes (T/F) :
S1: Sr2+ ions in very dilute solution do not give yellow precipitate with CrO2−4 ions.
S2: Ca2+ ions give a yellow precipitate in presence of ammonia with potassium ferrocyanide solution.
S3: Mg2+ ions in solution gives a gelatinous white precipitate of magnesium hydroxide with ammonia solution and the precipitate is readily soluble in solution and aqua regia.
S4: HgS forms soluble complex in excess of sulphide.

A
FTFF
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B
TTFF
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C
TFTT
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D
FFTT
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Solution

The correct option is C TFTT
In very dilute solutions, the ionic product of strontium chromate will be lower than the solubility product. Hence, the precipitate will not occur.Hence, statement 1 is true.
When calcium ions react with potassium ferrocyanide solution in presence of ammonia, yellow precipitate is not obtained. Instead, white precipitate of K(NH4)Ca(Fa(CN)6] is obtained. Hence, statement 2 is false.
Magnesium ions react with ammonia to form gelatinous white precipitate of magnesium hydroxide . It is readily soluble in solution and aqua regia. Mg2++2NH3+2H2OMg(OH)2+2NH4. Hence, statement 3 is true.

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