Consider the following statements. Let A={1,2,3,4}and B={5,7,9}
1.A×B=B×A2.n(A×B)=n(B×A)
Statement-1 is true.
Statement-2 is true
Both are true.
Both are false.
Step 1. Check statement :
Given A={1,2,3,4},B={5,7,9}
A×B={(1,5),(1,7),(1,9),(2,5),(2,7),(2,9),(3,5),(3,7),(3,9),(4,5),(4,7),(4,9)}B×A={(5,1),(5,2),(5,3),(5,4),(7,1),(7,2),(7,3),(7,4),(9,1),(9,2),(9,3),(9,4)}A×B≠B×A
Statement 1 is false.
Step 2. Check Statement 2:
n(A×B)=n(A)×n(B)=4×3=12n(B×A)=n(B)×n(A)=3×4=12n(A×B)=n(B×A)
Statement 2 is true.
Hence, the correct option is B.
Let A = {1, 2}, B = {1, 2, 3, 4}, C = {5, 6} and D = {5, 6, 7, 8}. Verify that :
(i) A×C⊂B×D
(ii) A×(B∩C)=(A×B)∩(A×C)
Let R be a relation on N×N defined by (a,b)R,(c,d)⇔a+d=b+c for all (a,b),(c,d)ϵN×N
Show that :
(i) (a, b) R (a, b) for all (a,b)ϵN×N
(ii) (a,b)R(c,d)⇒(c,d)R(a,b) for all (a,b),(c,d)ϵN×N
(iii) (a, b) R (c, d) and (c, d) R (e, f) ⇒ (a, b) R (e, f) for all (a, b), (c, d), (e, f) ϵN×N.
Let A = {1, 2}, B = {1, 2, 3, 4}, C = {5, 6} and D = {5, 6, 7, 8}. Verify that
(i) A × (B ∩ C) = (A × B) ∩ (A × C)
(ii) A × C is a subset of B × D