Consider the following transformations
$I . X e F_{6} + N a F ⟶ N a^{+} [X e F_{7}]^{-}$
$I I . 2 P C l_{5} (s) ⟶ [P C l_{4}]^{+} [P C l_{6}]^{-}$
$I I I . [A l (H_{2} O)_{6}]^{3 +} + H_{2} O ⟶ [A l (H_{2} O)_{5} O H]^{2 +} + H_{3} O^{+}$
Possible transformations are:

I, I I, I I I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I, I I I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I, I I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I, I I I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $I, I I, I I I$
All these transformations are possible.
In solid state, $P C l_{5}$ exists as $P C l_{4}^{+} P C l_{6}^{-}$ .
$X e F_{6}$ reacts with alkali metal fluoride and forms $X e F_{6} + N a F \to N a^{+} + X e F_{7}^{-}$
Also, as $A l^{3 +}$ ion is highly charged and small, so it attracts water molecules that bind to it via dative covalent bonds.
The $A l^{3 +}$ is able to attract the lone pair of electrons from the O-H bond, so the water molecule is split into $O H^{-}$ and $H^{+}$ .
$[A l (H_{2} O)_{6}]^{3 +} (a q) + H_{2} O (l) \to [A l (H_{2} O)_{5} O H]^{2 +} (a q) + H_{3} O^{+} (a q)$

Suggest Corrections

Similar questions

X e F_{6} + N a F \to N a^{+} [X e F_{7}]^{-}

2 P C l_{5} (s) \to [P C l_{4}]^{+} [P C l_{6}]^{-}

[A l (H_{2} O)_{6}]^{3 +} + H_{2} O \to [A l (H_{2} O)_{5} O H]^{2 +} + H_{3} O^{+}

Match the following

1. $P C l_{3}$ (i). 2 lone pairs (I) 5 Ligands

2. $C l F_{3}$ (ii). 3 lone pair (II) 3 Ligands

3. $X e F_{6}$ (iii). 0 lone pair (III) 6 Ligands

4. $S b C l_{5}$ (iv). 1 lone pairs (IV) 4 Ligands

C l_{3} C^{+}

C l_{2} C H^{+}

C l C H_{2}^{+}

C H_{3}^{+}

What will be (i), (ii) and (iii) if the following reaction is balanced?

$i) F e C l_{3} + (i i) M g O \to F e_{2} O_{3} + (i i i) M g C l_{2}$

Match the following:

Join BYJU'S Learning Program