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Question

Consider the follwoing reduction processes :
Zn2++2eZn(s); E0=0.76 V
Ca2++2eCa(s); E0=2.87 V
Mg2++2eMg(s); E0=2.36 V
Ni2++2eNi(s);E0=0.25 V

The reducing power of the metals increases in the order :

A
Ni<Zn<Mg<Ca
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B
Zn<Mg<Ni<Ca
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C
Ca<Mg<Zn<Ni
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D
Ca<Zn<Mg<Ni
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Solution

The correct option is A Ni<Zn<Mg<Ca
More the value of reduction potential higher will be the oxidising power of metal and lower will be the reducing power of metal.
Here, Ca2+/Ca couple has the least value of reduction potential so it readily go oxidation and its reducing power is high.

Thus, order of reducing power of metal is
Ni<Zn<Mg<Ca

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