Consider the follwoing reduction processes : Zn2++2e−→Zn(s);E0=−0.76V Ca2++2e−→Ca(s);E0=−2.87V Mg2++2e−→Mg(s);E0=−2.36V Ni2++2e−→Ni(s);E0=−0.25V
The reducing power of the metals increases in the order :
A
Ni<Zn<Mg<Ca
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B
Zn<Mg<Ni<Ca
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C
Ca<Mg<Zn<Ni
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D
Ca<Zn<Mg<Ni
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Solution
The correct option is ANi<Zn<Mg<Ca More the value of reduction potential higher will be the oxidising power of metal and lower will be the reducing power of metal.
Here, Ca2+/Ca couple has the least value of reduction potential so it readily go oxidation and its reducing power is high.
Thus, order of reducing power of metal is Ni<Zn<Mg<Ca