wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider the function, f(x)=x+1, 0x2, then fof(x) is

A
x+2, 0x1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x+2, 0x2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x+2, 0x4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x+2, 0x3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x+2, 0x1
fof(x)=f(f(x))=f(x)+1, 0f(x)2

fof(x)=(x+1)+1; 0x+12 and 0x2

fof(x)=x+2, 1x1 and 0x2

fof(x)=x+2, x[0,1]

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon