Consider the nitration of benzene using mixed conc. $H_{2} S O_{4}$ and $H N O_{3}$ . If a large amount of $K H S O_{4}$ is added to the mixture, the rate of nitration will be:

Slower

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Unchanged

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Doubled

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Faster

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
Slower

$H N O_{3} + H_{2} S O_{4} \to N O_{2}^{+} + H S O_{4}^{-} + H_{2} O$

$∴$ Addition of $K H S O_{4}$ will decrease the $N O_{2}^{+}$ concentration as it will furnish $H S O_{4}^{-}$ ions.

Suggest Corrections

Similar questions

H_{2} S O_{4}

H N O_{3}

K H S O_{4}

H N O_{3}

H_{2} S O_{4}

H N O_{3}

In the nitration of benzene using a mixture of conc. H₂SO₄ and conc. HNO₃ the Species which initiates the reaction is_______________

H N O_{3}

H_{2} S O_{4}

In the nitration of benzene with a mixture of conc $H N O_{3}$ and conc $H_{2} S O_{4}$ , the active species involved are

Join BYJU'S Learning Program