Question

Consider the nuclear reaction
$X^{200}\to A^{110}+B^{90}+energy$
If the binding energy per nucleon for $X,A$ and $B$ is $7.4MeV,8.2MeV$ and $8.2MeV$ respectively . What is the energy released?

• A. $200MeV$
• B. $160MeV$
• C. $110MeV$
• D. $90MeV$

Answer 1

The correct option is B $160MeV$

Energy released $=(E_A+E_B)-E_X$
$=(110\times 8.2+90\times 8.2)-200\times 7.4$
$=1640-1480$
$=160MeV$