Question

Consider the point $P(2,1);Q(0,0);R(4,-3)$ and the circle $S:x^2+y^2-5x+2y-5=0$

• A. Exactly one point lies outside S
• B. Exactly two point lies outside S
• C. All the three points lie outside S
• D. None of the point lies outside S

Answer 1

Answer: (D)

None of the point lies outside S

A point $(h,k)$ lies outside circle

$x^2+y^2-5x+2y-5=0$ if

$=h^2+k^2-5h+2k-5>0$

$\therefore$ $F$ or $P$ :

$=4+1-10+2-5<0$

$Q:$

$0+0-5<0$

$R:$

$16+9-20-6-5<0$

$\therefore$ None of the points lie outside the circle S