Question

Consider the reaction: $4Al+3O_2\to 2A{l}_2{O}_3$. Each particulate-level diagram represents an initial mixture of the reactants. Each molecule represents a mole of reactants.
Which initial mixture produces the MOST product?

• A. A
• B. B
• C. C
• D. D

Answer 1

The correct option is A A

Since, in A

4 molecules of $O_2$ is present which binds with 5 molecules of Al

Al is limiting reagent and produced 2.5 molecules of $A{l}_2{O}_3$

in C,

3 molecules of $O_2$ is present which binds with 4 molecules of Al and produce 2 molecules of $A{l}_2{O}_3$