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Question

Consider the reaction:

4NO2(g) + O2(g) 2N2O5(g), ΔrH = 111kJ. If N2O5(s) is formed instead of N2O5(g) in the above reaction, the ΔrH value will be:

(given, ΔH of sublimation for N2O5 is 54 kJ mol1)


A
+ 54 kJ
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B
+ 219 kJ
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C
− 219 J
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D
−165 kJ
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