Consider the reaction, aFeS2+bO2→cFe2O3+dSO2 Which of the following options are incorrect for the above reaction?
A
N- factor of FeS2 is 11
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B
The ratio of moles of a : b is 4 : 11
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C
The ratio of moles of a : b is 11 : 4
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D
The ratio of moles of c : d is 1 : 4
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Solution
The correct option is C The ratio of moles of a : b is 11 : 4 In the reaction the Oxidation state of Fe changes from +2 to +3 and of sulphur from -1 to +4 So, n-factor for FeS2 will be: (no. of atoms * change in O.S) for Fe + (no. of atoms * change in O.S) for S = 1*(3-2) + 2*(5) =11 n-factor for O2 = 2*2 =4 Now to balance the reaction we need to croos multiply the n-factors: So 4FeS2+11O2→2Fe2O3+8SO2 giving a= 4, b= 11, c= 2 d = 8 hence option (c) is the incorrect answer.