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Question

Consider the reactions,
NO2(g)12N2(g)+O2(g) K1
N2O4(g)2NO2(g) K2
Give the expression for equilibrium constant for the formation of N2O4 from N2 and O2:

A
12K1+1K2
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B
1K1K2
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C
K2K1
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D
1K21×1K2
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Solution

The correct option is D 1K21×1K2
Given:
NO2(g)12N2(g)+O2(g)...K1N2O4(g)N2O4(g)...K2

According to question
N2(g)+2O2(g)N2O4(g) ...Keq=?
Multiply equation (1) by 2 and reverse
N2(g)+2O2(g)2NO2(g)...K1=1K21(3)
On reversing equation 2
2NO2(g)N2O4(g)...K2=1K2(4)
On adding equations (3) and (4)
N2(g)+2O2(g)N2O4(g)Keq=1K21×1K2
Hence, option (a) is correct.

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