Consider the reactions, NO2(g)⇌12N2(g)+O2(g)⋯K1 N2O4(g)⇌2NO2(g)⋯K2
Give the expression for equilibrium constant for the formation of N2O4 from N2 and O2:
A
12K1+1K2
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B
√1K1K2
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C
K2K1
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D
1K21×1K2
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Solution
The correct option is D1K21×1K2 Given: NO2(g)⇌12N2(g)+O2(g)...K1N2O4(g)⇌N2O4(g)...K2
According to question N2(g)+2O2(g)⇌N2O4(g)...Keq=? Multiply equation (1)by 2 and reverse N2(g)+2O2(g)⇌2NO2(g)...K′1=1K21(3) On reversing equation2 2NO2(g)⇌N2O4(g)...K′2=1K2(4) On adding equations (3)and(4) N2(g)+2O2(g)⇌N2O4(g)Keq=1K21×1K2
Hence, option (a) is correct.