Question

Consider the situation shown in figure (32−E36). The switch is closed at t = 0 when the capacitors are uncharged. Find the charge on the capacitor C₁ as a function of time t.

Answer 1

The two capacitors are connected in series. Their equivalent capacitance,
$C_{eqv}=\frac{C_{\mathit{1}}{C}_{\mathit{2}}}{C_{\mathit{1}}+C_{\mathit{2}}}$
The growth of charge in the capacitors,
$q=C_{\mathrm{eqv}}\epsilon \left(1-{\mathrm{e}}^{-\frac{1}{r{C}_{\mathrm{eqv}}}}\right)$