Consider the word $^{'} P E R M U T A T I O N^{'}$ Out of all the permutations how many words start and end with $P$ and $M$ respectively?

9! \times 2!

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9!

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{9!}{2!}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{9!}{2!}$
$P - - -$ $M - --- -$

$P E R M U T A T I O N$
$9$ Blanks $⟶ 9$ letters
$2$ are repeated that is $T$ is present $2$ times
Number of ways
$= \frac{^{9} P_{9}}{2!} = \frac{9!}{2!}$

Suggest Corrections

Similar questions

Q. Consider the word

^{'} P E R M U T A T I O N^{'}

Out of all the permutations how many words start with the letter

M

Q. Consider the word '

P E R M U T A T I O N

' Out of all the permutations in how many words letter

T

will be in the middle?

Find the number of words that can be formed by consider of thing all the possible permutations of the word FATHER. How many of these words begin with A and end with R.

Q. Consider the word

^{'} P E R M U T A T I O N^{'}

. How many permutations can be made such that a word should always start with a vowel?

Q. Consider the word

^{'} P E R M U T A T I O N^{'}

. How many permutations can be made with all the vowels together?

Join BYJU'S Learning Program

Consider the word ′PERMUTATION′ Out of all the permutations how many words start and end with P and M respectively?

The correct option is C 9!2!P––– M–––––PERMUTATION9 Blanks ⟶9 letters 2 are repeated that is T is present 2 times Number of ways =9P92!=9!2!

Consider the word $^{'} P E R M U T A T I O N^{'}$ Out of all the permutations how many words start and end with $P$ and $M$ respectively?

The correct option is C $\frac{9!}{2!}$
$P - - -$ $M - --- -$

$P E R M U T A T I O N$
$9$ Blanks $⟶ 9$ letters
$2$ are repeated that is $T$ is present $2$ times
Number of ways
$= \frac{^{9} P_{9}}{2!} = \frac{9!}{2!}$