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Zener Diode

Consider the ...

Question

Consider the Zener voltage regulator shown in the figure below:

If the value of zener voltage is 5V then for the minimum value of $R_{L}$ for which Zener diode will be in breakdown is equal to ______ $k Ω .$

2.5

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Solution

The correct option is A 2.5

$I_{1} = \frac{20 - 5}{5 k Ω} = \frac{15 V}{5 k Ω} = 3 m A I f I_{z (m i n)} = 1 m A, I_{L (m a x)} = 3 m A - 1 m A = 2 m A ∴ R_{L (m i n)} = \frac{5}{2 \times 10^{- 3}} = 2.5 k Ω$

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