Consider two identically distributed zero-mean random variables U and V. Let the cumulative distribution functions of U and 2V be F(x) and G(x) respectively. Then, for all values of x
A
F(x)−G(x)≤0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
F(x)−G(x)≥0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
F(x)−G(x)x≤0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
F(x)−G(x).x≥0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is DF(x)−G(x).x≥0 By definition of c.d.f we have
F(x)=P[u≤x]
& G(x)=P[2v≤x]
=P(v≤x2)
Case I: When x > 0; F(x) > G(x)
Case II: when x < 0; F(x) < G(x) So in both cases [f(x)−G(x)]x≥0