Considering an ideal refrigerator, heat from its inside at a temperature of 277K is transferred to a room at temperature of 300K. Find the amount of heat extracted for each Joule of electrical energy consumed by refrigerator.
A
1J
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B
1.3J
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C
12J
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D
15J
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Solution
The correct option is C12J From the definition of coefficient of performance for a Carnot refrigerator (ideal refrigerator), β=Q2W=T2T1−T2 ⇒Q2=W(T2T1−T2)...(i)
Given, T2=277K,T1=300K W=Electrical work consumed by refrigerator W=1J
From Eq.(i) we get, Q2=1×277300−277≈12J
Hence amount of heat extracted by the refrigerator will be 12J