Considering the state of hybridization of carbon atoms, the molecule among the following which is linear is :

C H_{3} - C H \equiv C H - C H_{3}

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C H_{3} - C H = C H - C H_{3}

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C H_{2} = C H - C H_{2} - C \equiv C H

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C H_{3} - C H_{2} - C H_{2} - C H_{3}

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Solution

The correct option is A $C H_{3} - C H \equiv C H - C H_{3}$
The correct answer is $C H_{3} - C \equiv C - C H_{3}$ .
It is linear because $C_{2}$ and $C_{3}$ are $s p$ hybridised.

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Similar questions

What are the hybridization states of each carbon atom(s) in the following molecules ?

(i) $C H_{3} * C H_{2} C H_{2} C H_{3}$

(ii) $C H_{2} = C^{*} H - C H = C H_{2}$

(iii) $C H_{3} * C H = C H - C H_{3}$

(iv) $H - * C \equiv C - H$

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

A g N O_{3}

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

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