You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sigma Bond and Pi Bond

Considering x...

Question

Considering x-axis as the internuclear axis, which out of the following will not form a sigma bond.

1 s

and

1 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 s

and

2 p_{x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 p_{y}

and

2 p_{y}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 s

and

2 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 p_{y}$ and $2 p_{y}$
${2 p}_{y}$ and ${2 p}_{y}$ will not form a $σ$ bond because on taking x-axis as internuclear overlap sideway (lateral overlapping) resulting in the formation of a $π$ bond.

Suggest Corrections

Similar questions

Considering x-axis as the internuclear axis which out of the following will not form a sigma bond and why? (a) 1s and 1s (b) 1s and 2p_x (c) 2p_y and 2p_y (d) 1s and 2s.

Q. Considering

x -

axis as the internuclear axis, the overlap of which of the following orbitals will not form a sigma bond and why?

(a)

1 s

and

2 s

(b)

1 s

and

2 p_{x}

(c)

2 p_{y}

and

2 p_{y}

(d)

1 s

and

2 s

Q. Electronic configuration

1 s^{2} 2 s^{2} 2 p x^{1} 2 p y^{1} 2 p z^{1}

corresponds to :

Q. The electronic configuration

{1 s}^{2} {2 s}^{2} {2 p x}^{1} {2 p y}^{1} {2 p z}^{1}

is of:

Q. The relative energies of molecular orbitals are found to be in increasing order as follows-

σ (1 s) < σ^{*} (1 s) < σ (2 s) < σ^{*} (2 s) < [π (2 p_{y}) π (2 p_{z})] < σ (2 p_{x}) < [π^{*} (2 p_{y}) π^{*} (2 p_{z})] < σ^{*} (2 p_{x})

Join BYJU'S Learning Program

Considering x-axis as the internuclear axis, which out of the following will not form a sigma bond.

The correct option is B 2py and 2py2py and 2py will not form a σ bond because on taking x-axis as internuclear overlap sideway (lateral overlapping) resulting in the formation of a π bond.

The correct option is B $2 p_{y}$ and $2 p_{y}$
${2 p}_{y}$ and ${2 p}_{y}$ will not form a $σ$ bond because on taking x-axis as internuclear overlap sideway (lateral overlapping) resulting in the formation of a $π$ bond.