Construct a 2 × 2 matrix whose elements are aij=12 (2i – 3j)
A=[a11a12a21a22]
a11=12[2(1)−3(1)]=−12 a12=12[2(1)−3(2)]=−42=−2 a21=12[2(2)−3(1)]=12 a22=12[2(2)−3(2)]=−22=−1
Therefore A=⎡⎣−12−212−1⎤⎦