Construct a ∆ABC, in which AB = 6.5 cm, ∠B = 60° and BC = 5.5 cm. Also, construct a ∆AB'C' similar to ∆ABC,whose each side is $\frac{3}{2}$ times the corresponding sides of ∆ABC.

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Solution

Steps of Construction :

Step 1. Draw a line segment AB = 6.5 cm.
Step 2. With B as centre, draw an angle of 60^o .
Step 3. With B as centre and radius 5.5 cm, draw an arc cutting the angle at C.
Step 6. Join BC and AC.
Thus, △ABC is obtained .
Step 7. Extend AB to B', such that AB' = $\frac{3}{2}$ AB = $\frac{3}{2}$ (6.5) cm = 9.75 cm.
Step 8. Draw B'C' ∥ BC, cutting AC produced at C'.

Thus, △AB'C' is the required triangle, each of whose sides is $\frac{3}{2}$ the corresponding sides of ∆ABC.

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Construct a ∆ABC, in which AB = 6.5 cm, ∠B = 60° and BC = 5.5 cm. Also, construct a ∆AB'C' similar to ∆ABC,whose each side is 32 times the corresponding sides of ∆ABC.

Construct a ∆ABC, in which AB = 6.5 cm, ∠B = 60° and BC = 5.5 cm. Also, construct a ∆AB'C' similar to ∆ABC,whose each side is $\frac{3}{2}$ times the corresponding sides of ∆ABC.