Construct a $△ A B C$ in which $A B = 6.5 c m$ $, B C = 6.2 c m a n d A C = 5.3 c m$ .

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Solution

STEPS OF CONSTRUCTION;
STEP1:First we draw a line segment $B C = 6.2 c m$
STEP2:With $B$ as centre and $6.5 c m$ as radius draw an arc.
STEP3:With $C$ as centre and $5.3 c m$ as radius draw another arc which intersects the previous arc at point $A$ .
STEP4: Join $A B$ and $A C$ .
Hence $△ A B C$ is the required triangle.

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